Example
12 V divided by two 10 kΩ resistors with a 100 kΩ load
The source resistance is zero and the output load is 100 kΩ.
Unloaded output = 12 × 10 ÷ (10 + 10) = 6 V Effective lower resistance = 10 kΩ ∥ 100 kΩ = 9.091 kΩ Loaded output = 12 × 9.091 ÷ (10 + 9.091) = 5.714 V Loading error = (5.714 − 6) ÷ 6 = −4.76%
Result: 5.714 V loaded output.